Lower fence for reasonable data is Q 1 - MWL = 47 - 48 = 1. We find the maximum whisker length: MWL = IQR x 1.5 = 32 x 1.5 Their median is at the middle: Q 3 =įind the interquartile range: IQR = Q 3 - Q 1 = 79 - 47 = 32. Their median is at the middle: Q 1Ĥ: Data values above 61.5 are: 62, 78, 79, 83, 145. Is put in order from smallest to largest. Will use the following data representing tornadoes per year inĢ004 (Sullivan, 2nd edition, p. Mark the location of all your possible outliers Otherwise to the segment for the maximum.ġ8. Draw a line from the middle of the segmentįor Q3 to the middle of the segment for the new maximum (if you have one) or Minimum (if you have one) or otherwise to the segment for the minimum.ġ7. With horizontal lines through their top points and their bottom points.įrom the middle of the segment for Q1 to the middle of the segment for the new
Connect the segments for Q1, the median, and Q3 Use the maximum if there is no new maximum.ġ5. Use the minimum if there is no new minimum.
Their corresponding position on the number line. Minimum, Q1, the median, Q3, and the new maximum as short vertical lines above Number line that extends from the original minimum data value to the original It by the largest data value that is not a possible outlier. If the maximum is a possible outlier, replace It by the smallest data value that is not a possible outlier. If the minimum is a possible outlier, replace Reasonable data values should be at or below the Upper Fence.ĭata values below the Lower Fence or above the Upper Fence as possibleġ1. Reasonable data values should be at or above the Lower Fence.ĩ. This is the maximum whisker length, denotedĨ. This is the interquartile range, denoted IQR.ħ. Minimum, or smallest, data value, and the maximum, or largest, data value.Ħ. the middle data value when the scores are put in order. Good Modified Boxplots, Bad Modified Boxplots and Unmodified Boxplots Using TI 83/84 Calculator as Aid in Modified Boxplot ConstructionĬ. You have this constructed a box and whisker plot.B. From there, we make a jump to 2 38 then we make a very large dump to 602 Next, connect all your lines with a line going through the middles, other of them. Now that we have all of our numbers, it's a matter of marking them on our chart. When we average these two numbers, we get 3 38 This is equal to or third quarter mile. Since they're already in order, it's easy to cross off and see what we have to average. We must do the same with the data to the right of our median again. We can cross off and see that we have to average to 22 2 45 This works out to 2 33.5 and is also equal to our first quartile. That is everything to the left of our median. Since we have nine data points, we know their median is the fifth number I eat 2 56 After that, we need to find the median of our lower amount of data. I'm choosing to Canada for by fifties from 100 to 6 50 Next, find your media. We see that our minimum is 1 23 and our maximum a 602 Taking a look at this allows you to also make your number line. Arrange your data in order from minimum to maximum.
In order to make a box and whisker plot, you need your five point summary.
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